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How Do You Complete the Square?

Solving quadratics can be difficult. Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by factoring, using the square roots, or using the quadratic formula. The cool thing is that solving quadratic equations by completing the square will always work when solving quadratic equations, and the technique is a good tool to have in your math tool belt.

How Do You Complete the Square?

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Citation styles

APA style
How Do You Complete the Square?. (2010, October 18). In ClassBrain Math. Retrieved 22:35, May 23, 2012, from http://www.classbrainmath.com/2010/03/solving-a-quadratic-equations-by-completing-the-square/
MLA style
Cynthia Kirkeby, “How Do You Complete the Square?.” ClassBrain Math. 18 October 2010, 05:17 UTC. . 23 May 2012 <http://www.classbrainmath.com/2010/03/solving-a-quadratic-equations-by-completing-the-square/>.
MHRA style
Cynthia Kirkeby, 'How Do You Complete the Square?', ClassBrain Math, 18 October 2010, 05:17 UTC, <http://www.classbrainmath.com/2010/03/solving-a-quadratic-equations-by-completing-the-square/> [accessed 23 May 2012]
The Chicago Manual of Style
Cynthia Kirkeby, “How Do You Complete the Square?.” ClassBrain Math, http://www.classbrainmath.com/2010/03/solving-a-quadratic-equations-by-completing-the-square/ [accessed May 23, 2012].
CBE/CSE style
Cynthia Kirkeby, How Do You Complete the Square? [Internet]. ClassBrain Math; 2010 October 18, 05:17 UTC [cited 2012 May 23]. Available from: http://www.classbrainmath.com/2010/03/solving-a-quadratic-equations-by-completing-the-square/.
Bluebook style
How Do You Complete the Square?, http://www.classbrainmath.com/2010/03/solving-a-quadratic-equations-by-completing-the-square/ (last visited May. 23, 2012).
AMA style
Cynthia Kirkeby, How Do You Complete the Square?. ClassBrain Math. October 18, 2010, 05:17 UTC. Available at: http://www.classbrainmath.com/2010/03/solving-a-quadratic-equations-by-completing-the-square/. Accessed May 23, 2012.
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5 Responses to “How Do You Complete the Square?”

  1. Chrissy says:

    You could have just used the equation
    (b
    -
    2) ².

    *^ that is supposed to say b over 2 squared. then you could have added whatever that equals to both sides after subtracting your k value. Then whatever was in the parenthesis before you squared it would equal (X+_)²=y you wouldn’t have to foil thus saving you 2 steps.

    Heres how I solved it…

    x²+8x+10=y (subtract 10)
    -10=y-10
    x²+8x=10-y
    **heres where you do the equation I showed above**
    (8÷2)²
    (4)²
    16
    **add to both sides**
    x²+8x=y-10
    +16 +16
    x²+8x+16=y+6
    **instead of trying to find common factors that equal the equation above just use whatever you got in the ()**

    (x+4)²=y-6 (add 6)
    (x+4)²+6=y
    ^thats the answer you really dont have to solve with the ± considering from here you start to solve for the vertex since you just put the equation into vertex form from standard form….

    vertex (-4,6)
    line of symmetry x= -4

    TADAAA shortcut.

  2. admin says:

    Thanks for the alternate method. :)

  3. admin says:

    Simplifying
    4x^2 + 3x + -6 = y

    Isolate the 1st 2 terms:
    4x^2 + 3x + 0 = 6

    Divide through by 4 to bring 1st term to x^2
    x^2 + 3/4x + 0 = 6/4

    Take half of the coefficient (don’t forget the sign!) of the x-term, and square it. Add this square to both sides of the equation.
    x^2 + 3/4x + (3/8)^2 = 6/4 + (3/8)^2

    Simplify
    x^2 + 3/4x + 9/64 = 6/4 + 9/64

    Place into standard form
    (x + 3/8)^2 = 96/64 + 9/64

    Combine Like terms
    (x + 3/8)^2 = 105/64

    Square-root both sides, remembering the “±” on the right-hand side. Simplify as necessary.
    x + 3/8 = ±√105/8

    Solve for x
    Remember that the “±” means that you have two values for x.
    x = -3/8 + √105/8
    x = -3/8 – √105/8

  4. Emily says:

    THANK YOU! This video explained this to me better in five minutes, than my algebra two teacher has in the past week!

  5. admin says:

    You are very welcome. :)

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